Find lim_(x rarr4)(3x)/((x-2)(x+2)). Choose 1 answer: (A) (1)/(4) (B) (3)/(4) (c) 1 (D) The limit doesn't exist

Substitute x with 4: Substitute the value of x with 4 in the expression (3x)/((x-2)(x+2)) to see if the limit can be directly evaluated. lim_(x rarr4)(3x)/((x-2)(x+2)) = (3*4)/((4-2)(4+2))Calculate numerator and denominator: Calculate the values in the numerator and the denominator. (3*4)/((4-2)(4+2)) = 12/(2*6)Simplify the fraction: Simplify the fraction. 12/(2*6) = 12/12Find the limit: Simplify further to find the limit. 12/12 = 1

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Find
lim_(x rarr4)(3x)/((x-2)(x+2)).
Choose 1 answer:
(A)
(1)/(4)
(B)
(3)/(4)
(c) 1
(D) The limit doesn't exist

Find $\lim _{x \rightarrow 4} \frac{3 x}{(x-2)(x+2)}$ . $\newline$ Choose $1$ answer: $\newline$ (A) $\frac{1}{4}$ $\newline$ (B) $\frac{3}{4}$ $\newline$ (C) $1$ $\newline$ (D) The limit doesn't exist

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Math Problems

Algebra 2

Add, subtract, multiply, and divide polynomials

Full solution

Q. Find

\lim _{x \rightarrow 4} \frac{3 x}{(x-2)(x+2)}

\newline

Choose

1

answer:

\newline

(A)

\frac{1}{4}

\newline

(B)

\frac{3}{4}

\newline

(C)

1

\newline

(D) The limit doesn't exist

Substitute $x$ with $4$ : Substitute the value of $x$ with $4$ in the expression $\frac{3x}{(x-2)(x+2)}$ to see if the limit can be directly evaluated. $\newline$ $\lim_{x \rightarrow 4}\frac{3x}{(x-2)(x+2)} = \frac{3\cdot 4}{(4-2)(4+2)}$
Calculate numerator and denominator: Calculate the values in the numerator and the denominator. $\newline$ $(3\times4)/((4-2)(4+2)) = 12/(2\times6)$
Simplify the fraction: Simplify the fraction. $\frac{12}{2\times6} = \frac{12}{12}$
Find the limit: Simplify further to find the limit. $\frac{12}{12} = 1$