Find lim_(x rarr3)(-4)/(2x-5). Choose 1 answer: (A) -4 (B) (4)/(11) (c) 1 (D) The limit doesn't exist

Substitute value of x: Substitute the value of x into the limit expression. lim_(x rarr3)(-4)/(2x-5) = (-4)/(2*3-5)Perform arithmetic inside parentheses: Perform the arithmetic inside the parentheses. 2*3 - 5 = 6 - 5 = 1Substitute result into expression: Substitute the result from Step 2 into the limit expression. (-4)/(1) = -4Conclude the limit: Conclude the limit based on the calculations. The limit as x approaches 3 of (-4)/(2x-5) is -4.

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Find
lim_(x rarr3)(-4)/(2x-5).
Choose 1 answer:
(A) -4
(B)
(4)/(11)
(c) 1
(D) The limit doesn't exist

Find $\lim _{x \rightarrow 3} \frac{-4}{2 x-5}$ . $\newline$ Choose $1$ answer: $\newline$ (A) $-4$ $\newline$ (B) $\frac{4}{11}$ $\newline$ (C) $1$ $\newline$ (D) The limit doesn't exist

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Algebra 2

Add, subtract, multiply, and divide polynomials

Full solution

Q. Find

\lim _{x \rightarrow 3} \frac{-4}{2 x-5}

\newline

Choose

1

answer:

\newline

(A)

-4

\newline

(B)

\frac{4}{11}

\newline

(C)

1

\newline

(D) The limit doesn't exist

Substitute value of x: Substitute the value of $x$ into the limit expression. $\lim_{x \rightarrow 3}\left(\frac{-4}{2x-5}\right) = \frac{-4}{2\cdot 3-5}$
Perform arithmetic inside parentheses: Perform the arithmetic inside the parentheses. $2 \times 3 - 5 = 6 - 5 = 1$
Substitute result into expression: Substitute the result from Step $2$ into the limit expression. $\frac{-4}{1} = -4$
Conclude the limit: Conclude the limit based on the calculations. $\newline$ The limit as $x$ approaches $3$ of $\frac{-4}{2x-5}$ is $-4$ .