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Find lim_(x rarr3)(-4)/(2x-5). Choose 1 answer: (A) -4 (B) (4)/(11) (C) 1 (D) The limit doesn't exist

Find lim⁡x→3−42x−5 \lim _{x \rightarrow 3} \frac{-4}{2 x-5} .\newlineChoose 11 answer:\newline(A) −4-4\newline(B) 411 \frac{4}{11} \newline(C) 11\newline(D) The limit doesn't exist

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Q. Find lim⁡x→3−42x−5 \lim _{x \rightarrow 3} \frac{-4}{2 x-5} .\newlineChoose 11 answer:\newline(A) −4-4\newline(B) 411 \frac{4}{11} \newline(C) 11\newline(D) The limit doesn't exist
  1. Substitute value of x: Substitute the value of xx approaching 33 into the expression −42x−5\frac{-4}{2x-5} to see if the limit can be directly calculated.\newlineCalculation: −42⋅3−5=−46−5=−41=−4\frac{-4}{2\cdot 3-5} = \frac{-4}{6-5} = \frac{-4}{1} = -4
  2. Calculate limit: Since the substitution in Step 11 did not lead to an indeterminate form or infinity, the limit exists and is equal to the calculated value.

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