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Find 
lim_(x rarr2)(x+2)/(x-2).
Choose 1 answer:
(A) 4
(B) 1
(c) 0
(D) The limit doesn't exist

Find limx2x+2x2 \lim _{x \rightarrow 2} \frac{x+2}{x-2} .\newlineChoose 11 answer:\newline(A) 44\newline(B) 11\newline(C) 00\newlineD The limit doesn't exist

Full solution

Q. Find limx2x+2x2 \lim _{x \rightarrow 2} \frac{x+2}{x-2} .\newlineChoose 11 answer:\newline(A) 44\newline(B) 11\newline(C) 00\newlineD The limit doesn't exist
  1. Substitute and Calculate: Substitute xx with 22 in the function x+2x2\frac{x+2}{x-2}.
    limx2x+2x2=2+222\lim_{x \to 2}\frac{x+2}{x-2} = \frac{2+2}{2-2}
  2. Identify Undefined Expression: Calculate the numerator and the denominator separately.\newlineNumerator: 2+2=42+2 = 4\newlineDenominator: 22=02-2 = 0
  3. Analyzing Limit Behavior: We observe that the denominator becomes 00, which means the expression is undefined at x=2x=2. This indicates a potential limit issue, as division by zero is not allowed.
  4. Approaching from Left: Since the denominator is 00, we cannot directly calculate the limit by substitution. We need to analyze the behavior of the function as xx approaches 22 from both the left and the right.
  5. Approaching from Right: As xx approaches 22 from the left (x < 2), the numerator (x+2x+2) approaches 44, and the denominator (x2x-2) approaches a number slightly less than 00, making the fraction negative and very large in magnitude.
  6. Limit Does Not Exist: As xx approaches 22 from the right (x > 2), the numerator (x+2x+2) approaches 44, and the denominator (x2x-2) approaches a number slightly more than 00, making the fraction positive and very large in magnitude.
  7. Limit Does Not Exist: As xx approaches 22 from the right (x > 2), the numerator (x+2x+2) approaches 44, and the denominator (x2x-2) approaches a number slightly more than 00, making the fraction positive and very large in magnitude.Since the function approaches a large negative value from the left and a large positive value from the right, the limit does not exist because the left-hand limit and the right-hand limit are not equal.

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