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Find 
lim_(x rarr2)(x+2)/(x-2).
Choose 1 answer:
(A) 4
(B) 1
(C) 0
(D) The limit doesn't exist

Find limx2x+2x2 \lim _{x \rightarrow 2} \frac{x+2}{x-2} .\newlineChoose 11 answer:\newline(A) 44\newline(B) 11\newline(C) 00\newline(D) The limit doesn't exist

Full solution

Q. Find limx2x+2x2 \lim _{x \rightarrow 2} \frac{x+2}{x-2} .\newlineChoose 11 answer:\newline(A) 44\newline(B) 11\newline(C) 00\newline(D) The limit doesn't exist
  1. Substitute xx approaching 22: Substitute the value of xx approaching 22 into the function.\newlinelimx2x+2x2=2+222\lim_{x \to 2}\frac{x+2}{x-2} = \frac{2+2}{2-2}
  2. Perform calculation: Perform the calculation.\newline(2+2)/(22)=4/0(2+2)/(2-2) = 4/0
  3. Recognize division by zero: Recognize that division by zero is undefined. Since the denominator is 00, the expression 2+222\frac{2+2}{2-2} is undefined.
  4. Conclude limit does not exist: Conclude that the limit does not exist. Because we cannot divide by zero, the limit as xx approaches 22 does not exist.

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