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Find 
lim_(x rarr oo)(-5x^(4)+2x)/(x^(3)).
Choose 1 answer:
(A) 2
(B) 0
(C) -5
(D) The limit is unbounded

Find limx5x4+2xx3 \lim _{x \rightarrow \infty} \frac{-5 x^{4}+2 x}{x^{3}} .\newlineChoose 11 answer:\newline(A) 22\newline(B) 00\newline(C) 5-5\newline(D) The limit is unbounded

Full solution

Q. Find limx5x4+2xx3 \lim _{x \rightarrow \infty} \frac{-5 x^{4}+2 x}{x^{3}} .\newlineChoose 11 answer:\newline(A) 22\newline(B) 00\newline(C) 5-5\newline(D) The limit is unbounded
  1. Analyze Behavior: To find the limit of the given function as xx approaches infinity, we need to analyze the behavior of the numerator and the denominator separately. The highest power of xx in both the numerator and the denominator will dominate the behavior of the function as xx becomes very large.
  2. Divide by Highest Power: The highest power of xx in the numerator is x4x^4, and the highest power of xx in the denominator is x3x^3. To simplify the limit, we can divide both the numerator and the denominator by x3x^3, the highest power of xx in the denominator.
  3. Simplify Numerator: Dividing each term in the numerator by x3x^3 gives us:\newline(5x4)/x3+(2x)/x3(-5x^4)/x^3 + (2x)/x^3\newlineThis simplifies to:\newline5x+2x2-5x + \frac{2}{x^2}
  4. Take Limits: Now, we take the limit of each term as xx approaches infinity: limx(5x)=5×limx(x)=5×=\lim_{x \to \infty}(-5x) = -5 \times \lim_{x \to \infty}(x) = -5 \times \infty = -\infty limx(2x2)=2×limx(1x2)=2×0=0\lim_{x \to \infty}(\frac{2}{x^2}) = 2 \times \lim_{x \to \infty}(\frac{1}{x^2}) = 2 \times 0 = 0
  5. Add Limits: Adding the limits of the individual terms, we get: limx(5x+2x2)=+0=\lim_{x \to \infty}(-5x + \frac{2}{x^2}) = -\infty + 0 = -\infty
  6. Final Answer: Since the limit of the function as xx approaches \infty is -\infty, the limit is unbounded. Therefore, the correct answer is:\newline(D) The limit is unbounded

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