Find lim_(x rarr oo)(5x^(3)+2x^(2)-7)/(x^(4)+3x). Choose 1 answer: (A) 0 (B) 5 (C) (3)/(4) (D) The limit is unbounded

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Find  lim_(x rarr oo)(5x^(3)+2x^(2)-7)/(x^(4)+3x). Choose 1 answer: (A) 0 (B) 5 (C)  (3)/(4) (D) The limit is unbounded

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Analyze Behavior: To find the limit of the given function as x approaches infinity, we need to analyze the behavior of the numerator and the denominator separately. We look for the highest power of x in both the numerator and the denominator to determine the leading terms.Highest Power Analysis: The highest power of x in the numerator is x^3, and the highest power of x in the denominator is x^4. As x approaches infinity, the terms with lower powers of x become insignificant compared to the leading terms. Therefore, we can focus on the leading terms to determine the limit.Focus on Leading Terms: The leading term in the numerator is 5x^3, and the leading term in the denominator is x^4. As x approaches infinity, the ratio of these two terms will determine the limit. The ratio is 5x^3 / x^4, which simplifies to 5/x.Determine Ratio: As x approaches infinity, the term 5/x approaches 0 because the denominator grows much faster than the numerator. Therefore, the limit of the entire expression as x approaches infinity is 0.Limit Calculation: Comparing our result with the given options, we find that the correct answer is (A) 0.

Find $\lim _{x \rightarrow \infty} \frac{5 x^{3}+2 x^{2}-7}{x^{4}+3 x}$ . $\newline$ Choose $1$ answer: $\newline$ (A) $0$ $\newline$ (B) $5$ $\newline$ (C) $\frac{3}{4}$ $\newline$ (D) The limit is unbounded

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Find lim⁡x→∞5x3+2x2−7x4+3x \lim _{x \rightarrow \infty} \frac{5 x^{3}+2 x^{2}-7}{x^{4}+3 x} limx→∞​x4+3x5x3+2x2−7​.\newlineChoose 111 answer:\newline(A) 000\newline(B) 555\newline(C) 34 \frac{3}{4} 43​\newline(D) The limit is unbounded

Find $\lim _{x \rightarrow \infty} \frac{5 x^{3}+2 x^{2}-7}{x^{4}+3 x}$ . $\newline$ Choose $1$ answer: $\newline$ (A) $0$ $\newline$ (B) $5$ $\newline$ (C) $\frac{3}{4}$ $\newline$ (D) The limit is unbounded