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Find lim_(x rarr-3)g(x) for g(x)=x^(2)-x-1". "

Find lim⁡x→−3g(x) \lim _{x \rightarrow-3} g(x) for\newlineg(x)=x2−x−1.  g(x)=x^{2}-x-1 \text {. }

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Q. Find lim⁡x→−3g(x) \lim _{x \rightarrow-3} g(x) for\newlineg(x)=x2−x−1.  g(x)=x^{2}-x-1 \text {. }
  1. Identify function and limit: Identify the function and the limit to be found.\newlineWe are given the function g(x)=x2−x−1g(x) = x^2 - x - 1 and we need to find the limit as xx approaches −3-3.
  2. Substitute value into function: Substitute the value of −3-3 into the function g(x)g(x). Since the function g(x)g(x) is a polynomial, which is continuous everywhere, we can find the limit by direct substitution. g(−3)=(−3)2−(−3)−1g(-3) = (-3)^2 - (-3) - 1
  3. Calculate value of g(−3)g(-3): Calculate the value of g(−3)g(-3).
    g(−3)=9+3−1g(-3) = 9 + 3 - 1
    g(−3)=12−1g(-3) = 12 - 1
    g(−3)=11g(-3) = 11

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