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Find all angles, 
0^(@) <= theta < 360^(@), that satisfy the equation below, to the nearest tenth of a degree.

cot^(2)theta+4cot theta+3=0
Answer: 
theta=

Find all angles, 0^{\circ} \leq \theta<360^{\circ} , that satisfy the equation below, to the nearest tenth of a degree.\newlinecot2θ+4cotθ+3=0 \cot ^{2} \theta+4 \cot \theta+3=0 \newlineAnswer: θ= \theta=

Full solution

Q. Find all angles, 0θ<360 0^{\circ} \leq \theta<360^{\circ} , that satisfy the equation below, to the nearest tenth of a degree.\newlinecot2θ+4cotθ+3=0 \cot ^{2} \theta+4 \cot \theta+3=0 \newlineAnswer: θ= \theta=
  1. Solve Quadratic Equation: Let's first solve the quadratic equation in terms of cot(θ)\cot(\theta). The equation is cot2(θ)+4cot(θ)+3=0\cot^2(\theta) + 4\cot(\theta) + 3 = 0. This is a quadratic equation in standard form, where a=1a = 1, b=4b = 4, and c=3c = 3.
  2. Factor Quadratic Equation: We can factor the quadratic equation as (cot(θ)+1)(cot(θ)+3)=0(\cot(\theta) + 1)(\cot(\theta) + 3) = 0. This gives us two possible solutions for cot(θ)\cot(\theta): cot(θ)=1\cot(\theta) = -1 and cot(θ)=3\cot(\theta) = -3.
  3. Find Theta for Cot(1-1): Now we need to find the angles θ\theta that correspond to these cotangent values. For cot(θ)=1\cot(\theta) = -1, we know that cotangent is the reciprocal of tangent, so we are looking for angles where tan(θ)=1\tan(\theta) = -1. The angles with tangent of 1-1 in the range of 00 to 360360 degrees are 135135 degrees and 315315 degrees.
  4. Find Theta for Cot(3-3): For cot(θ)=3\cot(\theta) = -3, we need to use a calculator to find the angles that correspond to this cotangent value. Since cotangent is the reciprocal of tangent, we are looking for angles where tan(θ)=13\tan(\theta) = -\frac{1}{3}. We can use the inverse tangent function to find the reference angle, and then determine the angles in the specified range that have this tangent value.
  5. Combine Results: Using a calculator, we find that the reference angle for tan(θ)=13\tan(\theta) = -\frac{1}{3} is approximately 18.418.4 degrees. Since the tangent is negative in the second and fourth quadrants, the angles that satisfy this condition are 18018.4=161.6180 - 18.4 = 161.6 degrees and 36018.4=341.6360 - 18.4 = 341.6 degrees.
  6. Combine Results: Using a calculator, we find that the reference angle for tan(θ)=13\tan(\theta) = -\frac{1}{3} is approximately 18.418.4 degrees. Since the tangent is negative in the second and fourth quadrants, the angles that satisfy this condition are 18018.4=161.6180 - 18.4 = 161.6 degrees and 36018.4=341.6360 - 18.4 = 341.6 degrees.Combining the results from the two factors, we have four angles that satisfy the original equation: 135135 degrees, 315315 degrees, 161.6161.6 degrees, and 341.6341.6 degrees.

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