Q. Find all angles, 0∘≤θ<360∘, that satisfy the equation below, to the nearest tenth of a degree.cot2θ+4cotθ+3=0Answer: θ=
Solve Quadratic Equation: Let's first solve the quadratic equation in terms of cot(θ). The equation is cot2(θ)+4cot(θ)+3=0. This is a quadratic equation in standard form, where a=1, b=4, and c=3.
Factor Quadratic Equation: We can factor the quadratic equation as (cot(θ)+1)(cot(θ)+3)=0. This gives us two possible solutions for cot(θ): cot(θ)=−1 and cot(θ)=−3.
Find Theta for Cot(−1): Now we need to find the angles θ that correspond to these cotangent values. For cot(θ)=−1, we know that cotangent is the reciprocal of tangent, so we are looking for angles where tan(θ)=−1. The angles with tangent of −1 in the range of 0 to 360 degrees are 135 degrees and 315 degrees.
Find Theta for Cot(−3): For cot(θ)=−3, we need to use a calculator to find the angles that correspond to this cotangent value. Since cotangent is the reciprocal of tangent, we are looking for angles where tan(θ)=−31. We can use the inverse tangent function to find the reference angle, and then determine the angles in the specified range that have this tangent value.
Combine Results: Using a calculator, we find that the reference angle for tan(θ)=−31 is approximately 18.4 degrees. Since the tangent is negative in the second and fourth quadrants, the angles that satisfy this condition are 180−18.4=161.6 degrees and 360−18.4=341.6 degrees.
Combine Results: Using a calculator, we find that the reference angle for tan(θ)=−31 is approximately 18.4 degrees. Since the tangent is negative in the second and fourth quadrants, the angles that satisfy this condition are 180−18.4=161.6 degrees and 360−18.4=341.6 degrees.Combining the results from the two factors, we have four angles that satisfy the original equation: 135 degrees, 315 degrees, 161.6 degrees, and 341.6 degrees.
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