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Find $a_2$ and $a_3$ . $a_1=12$ $a_n=a_{n-1}+8$

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Solve equations: mixed review

Full solution

Q. Find

a_2

and

a_3

.

a_1=12

a_n=a_{n-1}+8

Find $a_2$ : To find $a_2$ , we use the given recursive formula $a_n=a_{n–1}+8$ , where $n$ represents the term number. Since $a_1=12$ , we can find $a_2$ by adding $8$ to $a_1$ . $\newline$ Calculation: $a_2 = a_1 + 8 = 12 + 8 = 20$ .
Find $a_3$ : Now, to find $a_3$ , we again use the recursive formula. We have just found $a_2$ , so we can find $a_3$ by adding $8$ to $a_2$ . $\newline$ Calculation: $a_3 = a_2 + 8 = 20 + 8 = 28$ .

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