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Find a point on the line and the line's slope. y+4=3(x+3)

Find a point on the line and the line's slope.\newliney+4=3(x+3) y+4=3(x+3)

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Full solution

Q. Find a point on the line and the line's slope.\newliney+4=3(x+3) y+4=3(x+3)
  1. Rewrite Equation: Rewrite the equation in slope-intercept form y=mx+by = mx + b. \newliney+4=3(x+3)y + 4 = 3(x + 3)\newliney=3x+9−4y = 3x + 9 - 4\newliney=3x+5y = 3x + 5
  2. Identify Slope: Identify the slope from the equation y=3x+5y = 3x + 5.\newlineSlope (mm) = 33
  3. Find Point: Find a point on the line by substituting x=0x = 0 into the equation.\newliney=3(0)+5y = 3(0) + 5\newliney=5y = 5\newlinePoint = (0,5)(0, 5)

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