Factor. x^(2)-11 x+28 Answer:

Identify Factors: To factor the quadratic expression x^2 - 11x + 28, we need to find two numbers that multiply to give the constant term (28) and add up to give the coefficient of the linear term (-11).List Factor Pairs: We list the pairs of factors of 28: (1, 28), (2, 14), (4, 7). We need to find a pair that adds up to -11.Find Correct Pair: The pair of factors of 28 that adds up to -11 is (4, 7), but since we need a sum of -11, we need both numbers to be negative: (-4, -7).Write as Binomials: We can now write the quadratic expression as a product of two binomials using the factors we found: x^2 - 11x + 28 = (x - 4)(x - 7).

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Factor. $\newline$ $x^{2}-11 x+28$ $\newline$ Answer:

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Precalculus

Solve exponential equations by rewriting the base

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Q. Factor.

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x^{2}-11 x+28

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Answer:

Identify Factors: To factor the quadratic expression $x^2 - 11x + 28$ , we need to find two numbers that multiply to give the constant term $(28)$ and add up to give the coefficient of the linear term $(-11)$ .
List Factor Pairs: We list the pairs of factors of $28$ : $(1, 28)$ , $(2, 14)$ , $(4, 7)$ . We need to find a pair that adds up to $-11$ .
Find Correct Pair: The pair of factors of $28$ that adds up to $-11$ is $(4, 7)$ , but since we need a sum of $-11$ , we need both numbers to be negative: $(-4, -7)$ .
Write as Binomials: We can now write the quadratic expression as a product of two binomials using the factors we found: $x^2 - 11x + 28 = (x - 4)(x - 7)$ .