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Factor the expression completely.

x^(4)-4x^(2)+3
Answer:

Factor the expression completely.\newlinex44x2+3 x^{4}-4 x^{2}+3 \newlineAnswer:

Full solution

Q. Factor the expression completely.\newlinex44x2+3 x^{4}-4 x^{2}+3 \newlineAnswer:
  1. Identify Polynomial Type: Identify the type of polynomial and look for a factoring strategy.\newlineThe given expression is a quadratic in form, but with a variable to the fourth power:\newlinex44x2+3x^4 - 4x^2 + 3\newlineThis can be treated as a quadratic with x2x^2 taking the place of xx.
  2. Factor as Quadratic: Factor the expression as if it were a quadratic.\newlineWe are looking for two binomials that multiply to give x44x2+3x^4 - 4x^2 + 3. The factors of 33 that subtract to give 44 are 1-1 and 3-3.\newline(x21)(x23)(x^2 - 1)(x^2 - 3)
  3. Check for Further Factoring: Check if the binomials can be factored further.\newlineThe binomial x21x^2 - 1 is a difference of squares and can be factored further.\newlinex21=(x+1)(x1)x^2 - 1 = (x + 1)(x - 1)\newlineThe binomial x23x^2 - 3 cannot be factored further over the integers.
  4. Write Completely Factored Form: Write the completely factored form of the expression.\newlineThe completely factored form of the expression is:\newline(x+1)(x1)(x23)(x + 1)(x - 1)(x^2 - 3)

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