Factor the expression completely. -16x^(4)+40 Answer:

Identify GCF: First, identify the greatest common factor (GCF) of the terms in the expression -16x^(4) and 40. The GCF of -16 and 40 is 8, and since there is no x term in 40, x cannot be part of the GCF. So, we factor out -8 from both terms.Factor Out GCF: Now, write the expression as a product of the GCF and the remaining terms. -16x^(4) + 40 = -8(2x^(4) - 5) Check to ensure that when you distribute -8 back into the parentheses, you get the original expression. -8 * 2x^(4) = -16x^(4) and -8 * (-5) = 40, which is correct.Write as Product: Next, look inside the parentheses to see if the expression 2x^(4) - 5 can be factored further. Since 2x^(4) is a term with an even power of x and 5 is a prime number, there are no common factors and it is not a difference of squares or any other factorable form. Therefore, the expression inside the parentheses cannot be factored further.Check Distribution: The expression is now fully factored. The completely factored form of the expression -16x^(4) + 40 is -8(2x^(4) - 5).

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Factor the expression completely.

-16x^(4)+40
Answer:

Factor the expression completely. $\newline$ $-16 x^{4}+40$ $\newline$ Answer:

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Q. Factor the expression completely.

\newline

-16 x^{4}+40

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Answer:

Identify GCF: First, identify the greatest common factor (GCF) of the terms in the expression $-16x^{4}$ and $40$ . The GCF of $-16$ and $40$ is $8$ , and since there is no $x$ term in $40$ , $x$ cannot be part of the GCF. So, we factor out $-8$ from both terms.
Factor Out GCF: Now, write the expression as a product of the GCF and the remaining terms. $\newline$ $-16x^{4} + 40 = -8(2x^{4} - 5)$ $\newline$ Check to ensure that when you distribute $-8$ back into the parentheses, you get the original expression. $\newline$ $-8 \times 2x^{4} = -16x^{4}$ and $-8 \times (-5) = 40$ , which is correct.
Write as Product: Next, look inside the parentheses to see if the expression $2x^{4} - 5$ can be factored further. Since $2x^{4}$ is a term with an even power of $x$ and $5$ is a prime number, there are no common factors and it is not a difference of squares or any other factorable form. Therefore, the expression inside the parentheses cannot be factored further.
Check Distribution: The expression is now fully factored. $\newline$ The completely factored form of the expression $-16x^{4} + 40$ is $-8(2x^{4} - 5)$ .