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Factor completely:

x^(2)(5x^(2)-6)-9x(5x^(2)-6)-10(5x^(2)-6)
Answer:

Factor completely:\newlinex2(5x26)9x(5x26)10(5x26) x^{2}\left(5 x^{2}-6\right)-9 x\left(5 x^{2}-6\right)-10\left(5 x^{2}-6\right) \newlineAnswer:

Full solution

Q. Factor completely:\newlinex2(5x26)9x(5x26)10(5x26) x^{2}\left(5 x^{2}-6\right)-9 x\left(5 x^{2}-6\right)-10\left(5 x^{2}-6\right) \newlineAnswer:
  1. Identify Common Factor: Identify the common factor in all three terms of the expression x2(5x26)9x(5x26)10(5x26)x^{2}(5x^{2}-6)-9x(5x^{2}-6)-10(5x^{2}-6). The common factor is (5x26)(5x^{2}-6).
  2. Factor Out Common Factor: Factor out the common factor (5x26)(5x^{2}-6) from each term.\newlineThe expression becomes (5x26)(x29x10)(5x^{2}-6)(x^{2}-9x-10).
  3. Factor Quadratic Expression: Now, factor the quadratic expression x29x10x^{2}-9x-10. This is a simple trinomial factoring problem. We look for two numbers that multiply to 10-10 and add up to 9-9. These numbers are 10-10 and +1+1. The factored form of x29x10x^{2}-9x-10 is (x10)(x+1)(x-10)(x+1).
  4. Combine Factored Expressions: Combine the factored quadratic with the common factor that was factored out earlier.\newlineThe completely factored form of the original expression is (5x26)(x10)(x+1)(5x^{2}-6)(x-10)(x+1).

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