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Factor completely.

5x^(2)+x-4
Answer:

Factor completely.\newline5x2+x4 5 x^{2}+x-4 \newlineAnswer:

Full solution

Q. Factor completely.\newline5x2+x4 5 x^{2}+x-4 \newlineAnswer:
  1. Identify Quadratic Expression: Identify the quadratic expression to be factored.\newlineThe given quadratic expression is 5x2+x45x^2 + x - 4. We need to find two numbers that multiply to give the product of the coefficient of x2x^2 (which is 55) and the constant term (which is 4-4), and at the same time, these two numbers should add up to give the coefficient of xx (which is 11).
  2. Find Two Numbers: Find two numbers that meet the criteria.\newlineWe are looking for two numbers that multiply to 20-20 (since 5×4=205 \times -4 = -20) and add up to 11. The numbers that meet these criteria are 55 and 4-4 because 5×4=205 \times -4 = -20 and 5+(4)=15 + (-4) = 1.
  3. Rewrite Middle Term: Rewrite the middle term using the two numbers found.\newlineWe can express the middle term xx as 5x4x5x - 4x, which are the two numbers we found in the previous step. So, the expression becomes:\newline5x2+5x4x45x^2 + 5x - 4x - 4
  4. Factor by Grouping: Factor by grouping.\newlineNow we group the terms to factor by grouping:\newline(5x2+5x)(4x+4)(5x^2 + 5x) - (4x + 4)\newlineWe can factor out a common factor from each group:\newline5x(x+1)4(x+1)5x(x + 1) - 4(x + 1)
  5. Factor out Common Binomial Factor: Factor out the common binomial factor.\newlineWe notice that (x+1)(x + 1) is a common factor in both terms, so we can factor it out:\newline(5x4)(x+1)(5x - 4)(x + 1)

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