Factor completely: (4x-7)(3x-5)-(3x-5)(3x+2) Answer:

Identify common factors: Identify common factors in both terms. We notice that (3x-5) is a common factor in both terms of the expression. (4x-7)(3x-5) - (3x-5)(3x+2)Factor out common factor: Factor out the common factor (3x-5). We can use the distributive property in reverse to factor out (3x-5). (3x-5)[(4x-7) - (3x+2)]Simplify expression inside brackets: Simplify the expression inside the brackets. Now we need to subtract the second term from the first term inside the brackets. (4x-7) - (3x+2) = 4x - 7 - 3x - 2Combine like terms: Combine like terms. Combine the x terms and the constant terms. 4x - 3x - 7 - 2 = x - 9Write final factored form: Write the final factored form. Now that we have simplified the expression inside the brackets, we can write the final factored form. (3x-5)(x-9)

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Algebra 2

Add, subtract, multiply, and divide polynomials

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Q. Factor completely:

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(4 x-7)(3 x-5)-(3 x-5)(3 x+2)

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Answer:

Identify common factors: Identify common factors in both terms. We notice that $(3x-5)$ is a common factor in both terms of the expression. $(4x-7)(3x-5) - (3x-5)(3x+2)$
Factor out common factor: Factor out the common factor $(3x-5)$ . $\newline$ We can use the distributive property in reverse to factor out $(3x-5)$ . $\newline$ $(3x-5)[(4x-7) - (3x+2)]$
Simplify expression inside brackets: Simplify the expression inside the brackets. $\newline$ Now we need to subtract the second term from the first term inside the brackets. $\newline$ $(4x-7) - (3x+2) = 4x - 7 - 3x - 2$
Combine like terms: Combine like terms. Combine the $x$ terms and the constant terms. $4x - 3x - 7 - 2 = x - 9$
Write final factored form: Write the final factored form. $\newline$ Now that we have simplified the expression inside the brackets, we can write the final factored form. $\newline$ $(3x-5)(x-9)$