Factor completely. -4x^(2)-44 x+104 Answer:

Identify common factor: Identify the common factor. The common factor in all terms is -4. Factor out -4 from each term. -4x^2 - 44x + 104 = -4(x^2 + 11x - 26)Factor out common factor: Factor the quadratic expression inside the parentheses. We need to find two numbers that multiply to -4 * -26 (which is 104) and add up to 11. The numbers that satisfy these conditions are 13 and -8. So, we can write the quadratic as: -4(x^2 + 11x - 26) = -4((x + 13)(x - 8))Factor quadratic expression: Check the factored form. Multiply the factors to ensure they give the original quadratic expression. -4(x + 13)(x - 8) = -4(x^2 - 8x + 13x - 104) = -4(x^2 + 5x - 104) = -4x^2 - 20x + 416 This is not the original expression, so there is a mistake.

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Algebra 2

Add, subtract, multiply, and divide polynomials

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Q. Factor completely.

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-4 x^{2}-44 x+104

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Answer:

Identify common factor: Identify the common factor. $\newline$ The common factor in all terms is $-4$ . $\newline$ Factor out $-4$ from each term. $\newline$ $-4x^2 - 44x + 104 = -4(x^2 + 11x - 26)$
Factor out common factor: Factor the quadratic expression inside the parentheses. $\newline$ We need to find two numbers that multiply to $-4 \times -26$ (which is $104$ ) and add up to $11$ . $\newline$ The numbers that satisfy these conditions are $13$ and $-8$ . $\newline$ So, we can write the quadratic as: $\newline$ $-4(x^2 + 11x - 26) = -4((x + 13)(x - 8))$
Factor quadratic expression: Check the factored form. $\newline$ Multiply the factors to ensure they give the original quadratic expression. $\newline$ $-4(x + 13)(x - 8) = -4(x^2 - 8x + 13x - 104)$ $\newline$ $= -4(x^2 + 5x - 104)$ $\newline$ $= -4x^2 - 20x + 416$ $\newline$ This is not the original expression, so there is a mistake.