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Factor completely.

3x^(2)-7x-10
Answer:

Factor completely.\newline3x27x10 3 x^{2}-7 x-10 \newlineAnswer:

Full solution

Q. Factor completely.\newline3x27x10 3 x^{2}-7 x-10 \newlineAnswer:
  1. Identify Quadratic Expression: Identify the quadratic expression to be factored.\newlineThe given quadratic expression is 3x27x103x^2 - 7x - 10. We need to find two numbers that multiply to give the product of the coefficient of x2x^2 (which is 33) and the constant term (which is 10-10), and add up to the coefficient of xx (which is 7-7).
  2. Find Suitable Numbers: Find two numbers that meet the criteria.\newlineWe are looking for two numbers that multiply to 30-30 (3×103 \times -10) and add up to 7-7. The numbers that meet these criteria are 10-10 and +3+3 because (10)×(+3)=30(-10) \times (+3) = -30 and (10)+(+3)=7(-10) + (+3) = -7.
  3. Rewrite Middle Term: Rewrite the middle term using the two numbers found.\newlineWe can express 7x-7x as 10x+3x-10x + 3x. So, the expression 3x27x103x^2 - 7x - 10 can be rewritten as 3x210x+3x103x^2 - 10x + 3x - 10.
  4. Factor by Grouping: Factor by grouping.\newlineNow we group the terms: 3x210x3x^2 - 10x + 3x103x - 10. We can factor out an xx from the first group and a 33 from the second group: x(3x10)+3(3x10)x(3x - 10) + 3(3x - 10).
  5. Factor out Common Binomial: Factor out the common binomial factor.\newlineSince both groups contain the common binomial factor (3x10)(3x - 10), we can factor it out: (3x10)(x+3)(3x - 10)(x + 3).

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