Factor completely. 2x^(2)-7x+3 Answer:

Question

Factor completely.  2x^(2)-7x+3 Answer:

Bytelearn · Accepted Answer

Identify Quadratic Expression: Identify the quadratic expression to be factored. The given quadratic expression is 2x^2 - 7x + 3. We need to find two binomials that multiply to give this expression.Find Multiplying Numbers: Find two numbers that multiply to the product of the coefficient of x^2 (which is 2) and the constant term (which is 3), and add up to the coefficient of x (which is -7). The product of the coefficient of x^2 and the constant term is 2 * 3 = 6. We need two numbers that multiply to 6 and add up to -7. The numbers that satisfy these conditions are -6 and -1 because -6 * -1 = 6 and -6 + -1 = -7.Rewrite Middle Term: Rewrite the middle term of the quadratic expression using the two numbers found in Step 2. The original expression is 2x^2 - 7x + 3. Rewrite -7x as -6x - x to get 2x^2 - 6x - x + 3.Factor by Grouping: Factor by grouping. Group the terms into two pairs: (2x^2 - 6x) and (-x + 3). Factor out the common factor from each pair. From the first pair, factor out 2x: 2x(x - 3). From the second pair, factor out -1: -1(x - 3). Now we have 2x(x - 3) - 1(x - 3).Factor out Common Factor: Factor out the common binomial factor. The common binomial factor is (x - 3). Factor this out to get (x - 3)(2x - 1).

Factor completely. $\newline$ $2 x^{2}-7 x+3$ $\newline$ Answer:

Full solution

More problems from Add, subtract, multiply, and divide polynomials

Related topics

Factor completely.\newline2x2−7x+3 2 x^{2}-7 x+3 2x2−7x+3\newlineAnswer:

Factor completely. $\newline$ $2 x^{2}-7 x+3$ $\newline$ Answer: