Factor completely. 2x^(2)-3x-5 Answer:

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Factor completely.  2x^(2)-3x-5 Answer:

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Identify Quadratic Expression: Identify the quadratic expression to be factored. The given quadratic expression is 2x^2 - 3x - 5. We need to find two binomials that multiply to give this expression.Set Up Factoring Problem: Set up the factoring problem. To factor the quadratic expression, we look for two numbers that multiply to give the product of the coefficient of x^2 (which is 2) and the constant term (which is -5), and add up to the coefficient of x (which is -3).Find Two Numbers: Find the two numbers. The product of the coefficient of x^2 and the constant term is 2 * -5 = -10. We need two numbers that multiply to -10 and add up to -3. The numbers that satisfy these conditions are -5 and 2 because (-5) * 2 = -10 and (-5) + 2 = -3.Write Factored Form: Write the quadratic expression in its factored form. Using the numbers found in Step 3, we can write the quadratic expression as: 2x^2 - 5x + 2x - 5 Now, we group the terms to factor by grouping: (2x^2 - 5x) + (2x - 5)Factor Each Group: Factor each group separately. From the first group (2x^2 - 5x), we can factor out an x: x(2x - 5) From the second group (2x - 5), we can factor out a 1: 1(2x - 5) Now we have: x(2x - 5) + 1(2x - 5)Factor Out Common Factor: Factor out the common binomial factor. The common binomial factor is (2x - 5), so we factor this out from both groups: (2x - 5)(x + 1)

Factor completely. $\newline$ $2 x^{2}-3 x-5$ $\newline$ Answer:

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Factor completely.\newline2x2−3x−5 2 x^{2}-3 x-5 2x2−3x−5\newlineAnswer:

Factor completely. $\newline$ $2 x^{2}-3 x-5$ $\newline$ Answer: