Factor completely: 25x^(2)(x-5)-(x-5) Answer:

Identify Common Factor: Identify the common factor in both terms. The common factor in both terms is (x-5).Factor Out Common Factor: Factor out the common factor (x-5). The expression can be rewritten as (x-5)(25x^2 - 1).Recognize Difference of Squares: Recognize that the second term is a difference of squares. 25x^2 - 1 can be factored as (5x + 1)(5x - 1) because it is a difference of squares where a^2 - b^2 = (a + b)(a - b).Write Final Factored Form: Write the final factored form. The complete factorization of the expression is (x-5)(5x + 1)(5x - 1).

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Factor completely:

25x^(2)(x-5)-(x-5)
Answer:

Factor completely: $\newline$ $25 x^{2}(x-5)-(x-5)$ $\newline$ Answer:

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Math Problems

Grade 8

Estimate positive square roots

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Q. Factor completely:

\newline

25 x^{2}(x-5)-(x-5)

\newline

Answer:

Identify Common Factor: Identify the common factor in both terms. $\newline$ The common factor in both terms is $(x-5)$ .
Factor Out Common Factor: Factor out the common factor $(x-5)$ . $\newline$ The expression can be rewritten as $(x-5)(25x^2 - 1)$ .
Recognize Difference of Squares: Recognize that the second term is a difference of squares. $25x^2 - 1$ can be factored as $(5x + 1)(5x - 1)$ because it is a difference of squares where $a^2 - b^2 = (a + b)(a - b)$ .
Write Final Factored Form: Write the final factored form. $\newline$ The complete factorization of the expression is $(x-5)(5x + 1)(5x - 1)$ .