Recognize squares: Recognize the expression as a difference of squares.The given expression is 1−x6y4. We can see that both 1 and x6y4 are perfect squares because 1 is the square of 1 and x6y4 is the square of x3y2.
Apply formula: Apply the difference of squares formula.The difference of squares formula is a2−b2=(a−b)(a+b). Here, a2 is 1 and b2 is x6y4, so a is 1 and b is x3y2.
Factor expression: Factor the expression using the difference of squares formula.Using the values of a and b from Step 2, we get:1−x6y4=(1−x3y2)(1+x3y2)
Check further factorization: Check for any further factorization.Both factors(1−x3y2) and (1+x3y2) cannot be factored further using real numbers, as they are not differences or sums of squares or any other factorable form.
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