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Let’s check out your problem:

f(x)={[-x-7," for ",x!=-3],[6," for ",x=-3]:}
Find 
f(-5)
Answer:

f(x)={x7amp; for amp;x36amp; for amp;x=3 f(x)=\left\{\begin{array}{lll} -x-7 & \text { for } & x \neq-3 \\ 6 & \text { for } & x=-3 \end{array}\right. \newlineFind f(5) f(-5) \newlineAnswer:\newline

Full solution

Q. f(x)={x7 for x36 for x=3 f(x)=\left\{\begin{array}{lll} -x-7 & \text { for } & x \neq-3 \\ 6 & \text { for } & x=-3 \end{array}\right. \newlineFind f(5) f(-5) \newlineAnswer:\newline
  1. Determine piecewise function: We need to determine which piece of the piecewise function to use for x=5x = -5. The function f(x)f(x) is defined by two expressions: one for when xx is not equal to 3-3, and one for when xx is equal to 3-3. Since 5-5 is not equal to 3-3, we use the first expression.
  2. Substitute x=5x = -5: Now we substitute x=5x = -5 into the first expression of the function: f(x)=x7f(x) = -x - 7.
  3. Calculate f(5)f(-5): Performing the substitution, we get f(5)=(5)7f(-5) = -(-5) - 7.
  4. Simplify expression: Simplifying the expression, we calculate f(5)=57f(-5) = 5 - 7.
  5. Final result: Subtracting 77 from 55, we find f(5)=2f(-5) = -2.