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f(x)={[(x+5)^(2)-8," for ",x!=-2],[-3," for ",x=-2]:}
Find 
f(-2)
Answer:

f(x)={(x+5)28amp; for amp;x23amp; for amp;x=2 f(x)=\left\{\begin{array}{lll} (x+5)^{2}-8 & \text { for } & x \neq-2 \\ -3 & \text { for } & x=-2 \end{array}\right. \newlineFind f(2) f(-2) \newlineAnswer:\newline

Full solution

Q. f(x)={(x+5)28 for x23 for x=2 f(x)=\left\{\begin{array}{lll} (x+5)^{2}-8 & \text { for } & x \neq-2 \\ -3 & \text { for } & x=-2 \end{array}\right. \newlineFind f(2) f(-2) \newlineAnswer:\newline
  1. Identify Function Part: First, we need to identify which part of the function definition applies to the value x=2x = -2. The function f(x)f(x) is defined differently for x=2x = -2 and for x2x \neq -2. Since we are looking for f(2)f(-2), we will use the part of the function definition that is specifically for x=2x = -2.
  2. Use Function Definition: According to the function definition, f(x)f(x) is equal to 3-3 when x=2x = -2. Therefore, f(2)=3f(-2) = -3. There is no need to perform any calculations since the function directly provides the value for x=2x = -2.