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f(x)={[x+4," for ",-5 <= x < 1],[-2," for ",x=1],[-(x-1)^(2)+6," for ",1 < x <= 4]:}
Find 
f(1)
Answer:

\[ f(x)=\left\{\begin{array}{lll} x+4 & \text { for } & -5 \leq x<1 \\ -2 & \text { for } & x=1 \\ -(x-1)^{2}+6 & \text { for } & 1

Full solution

Q. f(x)={x+4 for 5x<12 for x=1(x1)2+6 for 1<x4 f(x)=\left\{\begin{array}{lll} x+4 & \text { for } & -5 \leq x<1 \\ -2 & \text { for } & x=1 \\ -(x-1)^{2}+6 & \text { for } & 1<x \leq 4 \end{array}\right. \newlineFind f(1) f(1) \newlineAnswer:\newline
  1. Determine Value at x=1x=1: We need to determine the value of the function f(x)f(x) at x=1x = 1. The function f(x)f(x) is defined piecewise, meaning it has different expressions for different intervals of xx. We will look at the definition of f(x)f(x) and find the expression that applies when x=1x = 1.
  2. Find Expression for x=1x=1: According to the definition of f(x)f(x), the expression for f(x)f(x) when x=1x = 1 is simply 2-2. This is because the function explicitly defines f(1)f(1) as 2-2, without any need for further calculation.
  3. Conclude f(1)=2f(1)=-2: Since we have found the value of f(x)f(x) at x=1x = 1 directly from the function's definition, there is no need for additional steps or calculations. We can conclude that f(1)=2f(1) = -2.