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$f(x)={[x^(2)-3," for ",x!=0],[-5," for ",x=0]:} Find f(0) Answer:$

$f(x)=\left\{\begin{array}{lll} x^{2}-3 & \text { for } & x \neq 0 \\ -5 & \text { for } & x=0 \end{array}\right.$ $\newline$ Find $f(0)$ $\newline$ Answer: $\newline$

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Write an equation word problem

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Q.

f(x)=\left\{\begin{array}{lll} x^{2}-3 & \text { for } & x \neq 0 \\ -5 & \text { for } & x=0 \end{array}\right.

\newline

Find

f(0)

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Answer:

\newline

Define Function: The function $f(x)$ is defined piecewise, meaning it has different expressions for different values of $x$ . According to the definition of $f(x)$ , we have one expression for $x \neq 0$ and another for $x = 0$ . To find $f(0)$ , we need to use the expression that is defined for $x = 0$ .
Use Expression for $x=0$ : The expression for $f(x)$ when $x = 0$ is given directly in the function definition. It states that $f(0) = -5$ . Since we are looking for the value of the function at $x = 0$ , we use this part of the piecewise function.
Conclude $f(0)=-5$ : We can conclude that $f(0)$ is equal to $-5$ without any further calculations, as the function definition provides this value explicitly for $x = 0$ .

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