f(x)=3−2(x+1)Which of the following equivalent forms of the given function f displays, as the base or the coefficient, the y-coordinate of the y-intercept of the graph of y=f(x) in the xy-plane?A) f(x)=(31)(2x+2)B) f(x)=91(31)2xC) f(x)=81(−21x−21)D) f(x)=3(−2x−2)
Q. f(x)=3−2(x+1)Which of the following equivalent forms of the given function f displays, as the base or the coefficient, the y-coordinate of the y-intercept of the graph of y=f(x) in the xy-plane?A) f(x)=(31)(2x+2)B) f(x)=91(31)2xC) f(x)=81(−21x−21)D) f(x)=3(−2x−2)
Evaluate f(x) at x=0: To find the y-intercept of the graph of y=f(x), we need to evaluate f(x) when x=0.
Substitute x=0 into f(x): Substitute x=0 into the function f(x)=3−2(x+1).f(0)=3−2(0+1)=3−2=321=91. The y-coordinate of the y-intercept is 91.
Check options for y-intercept: Now we need to find which of the given options has the y-coordinate of the y-intercept 91 as the base or the coefficient.
Option A analysis: Option A: f(x)=(31)(2x+2) can be rewritten as f(x)=(31)2x+2. This does not have 91 as the base or the coefficient.
Option B analysis: Option B: f(x)=91(31)2x has the coefficient 91, which is the y-coordinate of the y-intercept.
Option C analysis: Option C: f(x)=81(−21x−21) can be rewritten as f(x)=(34)−21x−21=3−2x−2, which does not have 91 as the base or the coefficient.
Option D analysis: Option D: f(x)=3(−2x−2) is the same as the original function and does not have 91 as the base or the coefficient.