Q. The function f(x)=2x3−2x2+18x−18 is shown. If x−1 is a factor of f, what is the value of f(1)?
Given Factor of Function: We are given that x−1 is a factor of the function f(x)=2x3−2x2+18x−18. To find the value of f(1), we can simply substitute x=1 into the function, because if x−1 is a factor, then f(1) should be equal to 0.
Substitute x=1: Substitute x=1 into the function f(x):f(1)=2(1)3−2(1)2+18(1)−18
Calculate f(1): Calculate the value of f(1):f(1)=2(1)−2(1)+18(1)−18f(1)=2−2+18−18
Simplify Result: Simplify the expression: f(1)=0 This result is expected because x−1 is a factor of f, and therefore f(1) should indeed be 0.
More problems from Find limits using power and root laws