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The function f(x)=2x32x2+18x18 f(x) = 2x^3 - 2x^2 + 18x - 18 is shown. If x1 x - 1 is a factor of f f , what is the value of f(1) f(1) ?

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Q. The function f(x)=2x32x2+18x18 f(x) = 2x^3 - 2x^2 + 18x - 18 is shown. If x1 x - 1 is a factor of f f , what is the value of f(1) f(1) ?
  1. Given Factor of Function: We are given that x1x - 1 is a factor of the function f(x)=2x32x2+18x18f(x) = 2x^3 - 2x^2 + 18x - 18. To find the value of f(1)f(1), we can simply substitute x=1x = 1 into the function, because if x1x - 1 is a factor, then f(1)f(1) should be equal to 00.
  2. Substitute x=1x = 1: Substitute x=1x = 1 into the function f(x)f(x):f(1)=2(1)32(1)2+18(1)18f(1) = 2(1)^3 - 2(1)^2 + 18(1) - 18
  3. Calculate f(1)f(1): Calculate the value of f(1)f(1):f(1)=2(1)2(1)+18(1)18f(1) = 2(1) - 2(1) + 18(1) - 18f(1)=22+1818f(1) = 2 - 2 + 18 - 18
  4. Simplify Result: Simplify the expression: f(1)=0f(1) = 0 This result is expected because x1x - 1 is a factor of ff, and therefore f(1)f(1) should indeed be 00.

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