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Let’s check out your problem:

f(x)={[2x-1," for ",x!=3],[-2," for ",x=3]:}
Find 
f(3)
Answer:

f(x)={2x1amp; for amp;x32amp; for amp;x=3 f(x)=\left\{\begin{array}{lll} 2 x-1 & \text { for } & x \neq 3 \\ -2 & \text { for } & x=3 \end{array}\right. \newlineFind f(3) f(3) \newlineAnswer:\newline

Full solution

Q. f(x)={2x1 for x32 for x=3 f(x)=\left\{\begin{array}{lll} 2 x-1 & \text { for } & x \neq 3 \\ -2 & \text { for } & x=3 \end{array}\right. \newlineFind f(3) f(3) \newlineAnswer:\newline
  1. Define function f(x)f(x): The function f(x)f(x) is defined piecewise, meaning it has different expressions for different values of xx. We need to find the value of f(x)f(x) when xx is exactly 33. According to the definition of the function, f(x)f(x) is equal to 2-2 when xx equals 33.\newlineCalculation: f(x)f(x)00