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f) 
10p^(2)-9p+2

f) 10p29p+2 10 p^{2}-9 p+2

Full solution

Q. f) 10p29p+2 10 p^{2}-9 p+2
  1. Identify Expression: Identify the expression to be factored.\newlineThe given expression is a quadratic trinomial: 10p29p+210p^2 - 9p + 2.
  2. Find Two Numbers: Look for two numbers that multiply to give the product of the coefficient of p2p^2 (which is 1010) and the constant term (which is 22), and add up to the coefficient of pp (which is 9-9).\newlineThe two numbers that satisfy these conditions are 1-1 and 10-10, because (1)×(10)=10(-1) \times (-10) = 10 and (1)+(10)=11(-1) + (-10) = -11, which is not 9-9. This is a mistake, we need to find the correct pair of numbers.

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