Bytelearn - cat image with glassesAI tutor

Welcome to Bytelearn!

Let’s check out your problem:

Express the given expression as an integer or as a fraction in simplest form.

log_(3)((1)/(3^(7)))
Answer:

Express the given expression as an integer or as a fraction in simplest form.\newlinelog3(137) \log _{3}\left(\frac{1}{3^{7}}\right) \newlineAnswer:

Full solution

Q. Express the given expression as an integer or as a fraction in simplest form.\newlinelog3(137) \log _{3}\left(\frac{1}{3^{7}}\right) \newlineAnswer:
  1. Understand the logarithm expression: Understand the logarithm expression log3(137)\log_{3}\left(\frac{1}{3^{7}}\right). We need to express the logarithm of a fraction where the numerator is 11 and the denominator is 33 raised to the power of 77, with base 33.
  2. Apply logarithm power rule: Apply the logarithm power rule.\newlineThe power rule of logarithms states that logb(ac)=clogb(a)\log_b(a^c) = c \cdot \log_b(a). In this case, we can apply the power rule to the denominator of the fraction.\newlinelog3(137)=log3(1)log3(37)\log_{3}\left(\frac{1}{3^{7}}\right) = \log_{3}(1) - \log_{3}(3^{7})
  3. Evaluate log3(1)\log_{3}(1): Evaluate log3(1)\log_{3}(1).\newlineThe logarithm of 11 to any base is always 00 because any number raised to the power of 00 is 11.\newlinelog3(1)=0\log_{3}(1) = 0
  4. Apply power rule to log3(37)\log_{3}(3^7): Apply the power rule to log3(37)\log_{3}(3^{7}). Using the power rule, we can take the exponent out in front of the logarithm. log3(37)=7×log3(3)\log_{3}(3^{7}) = 7 \times \log_{3}(3)
  5. Evaluate log3(3)\log_{3}(3): Evaluate log3(3)\log_{3}(3). The logarithm of a number to the same base is 11 because any number raised to the power of 11 is itself. log3(3)=1\log_{3}(3) = 1
  6. Combine results from Step 33 and Step 55: Combine the results from Step 33 and Step 55.\newlineNow we can combine the results to find the value of the original expression.\newlinelog3(137)=0(7×1)\log_{3}\left(\frac{1}{3^{7}}\right) = 0 - (7 \times 1)
  7. Simplify the expression: Simplify the expression.\newlineSubtracting 77 times 11 from 00 gives us 7-7.\newlinelog3(137)=07=7\log_{3}\left(\frac{1}{3^{7}}\right) = 0 - 7 = -7

More problems from Quotient property of logarithms