Q. Expand the logarithm fully using the properties of logs. Express the final answer in terms of logx,logy, and logz.logx2yz4Answer:
Apply Quotient Rule: Let's start by applying the quotient rule of logarithms, which states that log(ba)=log(a)−log(b). So, we have log(x2yz4)=log(yz4)−log(x2).
Deal with First Term: Now, let's deal with the first term, log(yz4). The square root is the same as raising to the power of 21, so we can rewrite this as log((yz4)21).Using the power rule of logarithms, which states that log(an)=nlog(a), we get log((yz4)21)=(21)log(yz4).
Apply Product Rule: Next, we apply the product rule of logarithms to the term log(yz4), which states that log(ab)=log(a)+log(b). This gives us (21)⋅(log(y)+log(z4)).
Apply Power Rule: Now, let's apply the power rule again to log(z4), which gives us log(z4)=4log(z). So, we have (21)⋅(log(y)+4log(z)).
Distribute Coefficients: We can distribute the 21 to both terms inside the parenthesis, resulting in (21)log(y)+(21)⋅4log(z), which simplifies to (21)log(y)+2log(z).
Address Second Term: Now, let's address the second term from step 1, log(x2). Applying the power rule of logarithms, we get log(x2)=2⋅log(x).
Combine All Terms: Finally, we combine all the terms together to get the expanded form of the original logarithm.We have log(yz4)−log(x2) which becomes (21)log(y)+2log(z)−2log(x).
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