The equation for line f can be written as y=2x+3. Line g is parallel to line f and passes through the point (5,6). What is the equation of line g ?

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Identify slope of line f: Identify the slope of line f. The equation of line f is given as y = 2x + 3. The slope-intercept form of a line is y = mx + b, where m is the slope and b is the y-intercept. By comparing the given equation with the slope-intercept form, we can see that the slope (m) of line f is 2.Determine slope of line g: Determine the slope of line g. Since line g is parallel to line f, it will have the same slope. Therefore, the slope (m) of line g is also 2.Use point to find y-intercept: Use the point (5,6) to find the y-intercept (b) of line g. We know that line g passes through the point (5,6) and has a slope of 2. We can use the point-slope form of the equation of a line, which is y - y1 = m(x - x1), where (x1, y1) is a point on the line. Plugging in the values, we get: 6 - y1 = 2(5 - x1) Since (x1, y1) is (5,6), we have: 6 - 6 = 2(5 - 5) This simplifies to: 0 = 2(0) This equation is true, but it does not help us find the y-intercept. We need to use the slope-intercept form y = mx + b to find b. Let's plug the point (5,6) into this form: 6 = 2(5) + b 6 = 10 + b Now, we solve for b: 6 - 10 = b -4 = bWrite equation of line g: Write the equation of line g. Now that we have the slope (m = 2) and the y-intercept (b = -4), we can write the equation of line g in slope-intercept form: y = 2x - 4

The equation for line $f$ can be written as $y=2 x+3$ . Line $g$ is parallel to line $f$ and passes through the point $(5,6)$ . What is the equation of line $g$ ?

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The equation for line f f f can be written as y=2x+3 y=2 x+3 y=2x+3. Line g g g is parallel to line f f f and passes through the point (5,6) (5,6) (5,6). What is the equation of line g g g ?

The equation for line $f$ can be written as $y=2 x+3$ . Line $g$ is parallel to line $f$ and passes through the point $(5,6)$ . What is the equation of line $g$ ?