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Evalutate (h∘g)(−6)(h \circ g)(-6) \newlineg(b)=5b−9g(b) =5b-9 \newlineh(b)=(b−1)2h(b) = (b-1)^{2}

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Full solution

Q. Evalutate (h∘g)(−6)(h \circ g)(-6) \newlineg(b)=5b−9g(b) =5b-9 \newlineh(b)=(b−1)2h(b) = (b-1)^{2}
  1. Identify g(−6)g(-6): Identify g(−6)g(-6) using the function g(b)=5b−9g(b) = 5b - 9.\newlineCalculation: g(−6)=5(−6)−9=−30−9=−39g(-6) = 5(-6) - 9 = -30 - 9 = -39.
  2. Calculate g(−6)g(-6): Next, find h(g(−6))h(g(-6)) using the function h(b)=(b−1)2h(b) = (b - 1)^2.\newlineCalculation: h(−39)=(−39−1)2=(−40)2=1600h(-39) = (-39 - 1)^2 = (-40)^2 = 1600.

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