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Let’s check out your problem:
Evaluate the expression.
\newline
4
5
×
1
2
−
1
5
\frac{4}{5} \times \frac{1}{2} - \frac{1}{5}
5
4
×
2
1
−
5
1
\newline
Write your answer in simplest form.
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Math Problems
Grade 7
Evaluate numerical expressions involving fractions
Full solution
Q.
Evaluate the expression.
\newline
4
5
×
1
2
−
1
5
\frac{4}{5} \times \frac{1}{2} - \frac{1}{5}
5
4
×
2
1
−
5
1
\newline
Write your answer in simplest form.
Given expression:
\newline
4
5
×
1
2
−
1
5
\frac{4}{5} \times \frac{1}{2} - \frac{1}{5}
5
4
×
2
1
−
5
1
Multiply
fractions
:
Multiply
4
5
\frac{4}{5}
5
4
by
1
2
\frac{1}{2}
2
1
.
\newline
4
5
×
1
2
=
4
×
1
5
×
2
=
4
10
\frac{4}{5} \times \frac{1}{2} = \frac{4 \times 1}{5 \times 2} = \frac{4}{10}
5
4
×
2
1
=
5
×
2
4
×
1
=
10
4
Simplify result:
Simplify
4
10
\frac{4}{10}
10
4
.
\newline
4
10
=
2
5
\frac{4}{10} = \frac{2}{5}
10
4
=
5
2
Subtract fractions:
Subtract
1
5
\frac{1}{5}
5
1
from
2
5
\frac{2}{5}
5
2
.
\newline
2
5
−
1
5
=
2
−
1
5
=
1
5
\frac{2}{5} - \frac{1}{5} = \frac{2 - 1}{5} = \frac{1}{5}
5
2
−
5
1
=
5
2
−
1
=
5
1
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Multiply.
\newline
(
3
5
)
×
(
1
6
)
=
(\frac{3}{5})\times(\frac{1}{6})=
(
5
3
)
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Submit
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2
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Question
Simplify to a single power of
3
3
3
:
\newline
3
5
×
3
2
3^{5} \times 3^{2}
3
5
×
3
2
\newline
Answer:
3
□
3 ^\square
3
□
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Question
Simplify to a single power of
6
6
6
:
\newline
6
3
⋅
6
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6
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⋅
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\newline
Answer:
6
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Question
What value of
z
z
z
makes the equation below true?
\newline
9
z
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2
=
79
9 z-2=79
9
z
−
2
=
79
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3
3
3
\newline
9
9
9
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13
13
13
\newline
79
79
79
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Question
What value of
y
y
y
makes the equation below true?
\newline
5
y
+
2
=
17
5 y+2=17
5
y
+
2
=
17
\newline
2
2
2
\newline
3
3
3
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6
6
6
\newline
17
17
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