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Let’s check out your problem:
Evaluate the expression.
\newline
1
2
×
1
4
+
1
\frac{1}{2} \times \frac{1}{4} + 1
2
1
×
4
1
+
1
\newline
Write your answer as a
fraction
or as a whole or mixed number.
\newline
______
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Math Problems
Grade 7
Evaluate numerical expressions involving fractions
Full solution
Q.
Evaluate the expression.
\newline
1
2
×
1
4
+
1
\frac{1}{2} \times \frac{1}{4} + 1
2
1
×
4
1
+
1
\newline
Write your answer as a fraction or as a whole or mixed number.
\newline
______
Multiply Fractions:
First, we need to multiply the
fractions
1
1
1
/
2
2
2
and
1
1
1
/
4
4
4
.
\newline
Calculation:
1
2
×
1
4
=
1
×
1
2
×
4
=
1
8
\frac{1}{2} \times \frac{1}{4} = \frac{1 \times 1}{2 \times 4} = \frac{1}{8}
2
1
×
4
1
=
2
×
4
1
×
1
=
8
1
Add to
1
1
1
:
Next, add the result from the first step to
1
1
1
.
\newline
Calculation:
1
8
+
1
=
1
8
+
8
8
=
9
8
\frac{1}{8} + 1 = \frac{1}{8} + \frac{8}{8} = \frac{9}{8}
8
1
+
1
=
8
1
+
8
8
=
8
9
More problems from Evaluate numerical expressions involving fractions
Question
Find `x` value
\newline
2
x
−
2
=
0
2x-2=0
2
x
−
2
=
0
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Posted 8 months ago
Question
2
x
+
3
=
2
2x+3 = 2
2
x
+
3
=
2
\newline
Find
x
x
x
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Question
2
+
8
2+8
2
+
8
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6
+
12
6+12
6
+
12
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Posted 8 months ago
Question
Multiply.
\newline
(
3
5
)
×
(
1
6
)
=
(\frac{3}{5})\times(\frac{1}{6})=
(
5
3
)
×
(
6
1
)
=
\newline
Submit
\newline
Get help
Get tutor help
Posted 8 months ago
Question
2
x
+
3
=
2
2x+3 = 2
2
x
+
3
=
2
\newline
Find
x
.
x.
x
.
Get tutor help
Posted 8 months ago
Question
Simplify to a single power of
3
3
3
:
\newline
3
5
×
3
2
3^{5} \times 3^{2}
3
5
×
3
2
\newline
Answer:
3
□
3 ^\square
3
□
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Posted 8 months ago
Question
Simplify to a single power of
6
6
6
:
\newline
6
3
⋅
6
2
6^{3} \cdot 6^{2}
6
3
⋅
6
2
\newline
Answer:
6
□
6 ^\square
6
□
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Posted 8 months ago
Question
What value of
z
z
z
makes the equation below true?
\newline
9
z
−
2
=
79
9 z-2=79
9
z
−
2
=
79
\newline
3
3
3
\newline
9
9
9
\newline
13
13
13
\newline
79
79
79
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Posted 8 months ago
Question
What value of
y
y
y
makes the equation below true?
\newline
5
y
+
2
=
17
5 y+2=17
5
y
+
2
=
17
\newline
2
2
2
\newline
3
3
3
\newline
6
6
6
\newline
17
17
17
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Posted 8 months ago
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