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Evaluate:

log_(27)((1)/(9))
Answer:

Evaluate:\newlinelog2719 \log _{27} \frac{1}{9} \newlineAnswer:

Full solution

Q. Evaluate:\newlinelog2719 \log _{27} \frac{1}{9} \newlineAnswer:
  1. Understand logarithm and base: Understand the logarithm and its base.\newlineWe are given the logarithm log2719\log_{27} \frac{1}{9}. We need to evaluate this expression.
  2. Express in terms of base: Express 19\frac{1}{9} in terms of the base 2727. We know that 2727 is 333^3 and 99 is 323^2. Therefore, 19\frac{1}{9} can be written as 323^{-2}.
  3. Use change of base formula: Use the change of base formula.\newlineThe change of base formula states that logab=logcblogca\log_{a}b = \frac{\log_{c}b}{\log_{c}a}. We can use the base of 33 for both the numerator and the denominator.\newlinelog2732=log332log327\log_{27}3^{-2} = \frac{\log_{3}3^{-2}}{\log_{3}27}
  4. Evaluate logarithms: Evaluate the logarithms.\newlineSince 2727 is 333^3, log327\log_{3}{27} is 33. And since the base and the argument of the numerator are the same, log332\log_{3}{3^{-2}} is 2-2.\newlineSo, log2732=23\log_{27}{3^{-2}} = \frac{-2}{3}
  5. Simplify expression: Simplify the expression.\newlineThe expression (2)/3(-2) / 3 simplifies to 2/3-2/3.

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