Eva maintained an average speed of 35mph for the first m hours of her road trip. For the next n hours of the trip, she drove at an average speed of 60mph. Eva drove a total of 225 miles in 4.5 hours. Which of the following systems of equations could be used to find how many miles Eva drove in the first m hours of the trip?Choose 1 answer:(A) m+n=22535m+60n=4.5(B) m+n=4.535m+60n=225(C) m+n=22560m+35n=4.5(D) m+n=4.560m+35n=225
Q. Eva maintained an average speed of 35mph for the first m hours of her road trip. For the next n hours of the trip, she drove at an average speed of 60mph. Eva drove a total of 225 miles in 4.5 hours. Which of the following systems of equations could be used to find how many miles Eva drove in the first m hours of the trip?Choose 1 answer:(A) m+n=22535m+60n=4.5(B) m+n=4.535m+60n=225(C) m+n=22560m+35n=4.5(D) m+n=4.560m+35n=225
Understand the problem: Understand the problem.Eva drove for a total of 4.5 hours and covered 225 miles. She drove for m hours at 35 mph and for n hours at 60 mph. We need to find a system of equations that relates the time and distance for each part of the trip.
Set up first equation: Set up the first equation based on the total time.The total time driven was 4.5 hours, which is the sum of the time driven at 35 mph (m hours) and the time driven at 60 mph (n hours). Therefore, the first equation is:m+n=4.5
Set up second equation: Set up the second equation based on the total distance.The total distance driven was 225 miles. Eva drove m hours at 35 mph and n hours at 60 mph. The distance driven at 35 mph is 35m and the distance driven at 60 mph is 60n. The sum of these distances should equal the total distance driven, which is 225 miles. Therefore, the second equation is:m0
Identify system of equations: Identify the correct system of equations.Based on the equations from Step 2 and Step 3, the correct system of equations is:m+n=4.535m+60n=225This corresponds to option (B).
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