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Does $(3,\ 10)$ make the inequality 4x + 20y > 5 true? $\newline$ Choices: $\newline$ (A)yes $\newline$ (B)no

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Does (x, y) satisfy the inequality?

Full solution

Q. Does

(3,\ 10)

make the inequality

4x + 20y > 5

true?

\newline

Choices:

\newline

(A)yes

\newline

(B)no

Substitute values into inequality: Substitute the values $(3, 10)$ into the inequality 4x + 20y > 5. The substituted inequality is 4(3) + 20(10) > 5.
Calculate left side: Calculate the left side of the inequality $4(3) + 20(10)$ . Simplify it to get $4\times 3 + 20\times 10 = 12 + 200 = 212$ .
Determine if inequality is true: The inequality 4(3) + 20(10) > 5 becomes 212 > 5. Now, determine if the point $(3, 10)$ makes the inequality 4x + 20y > 5 true. Since $212$ is greater than $5$ , the statement 212 > 5 is true.

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