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Does $(1,\,1)$ make the inequality $3x + 16y \leq 19$ true? $\newline$ Choices: $\newline$ (A)yes $\newline$ (B)no

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Does (x, y) satisfy the inequality?

Full solution

Q. Does

(1,\,1)

make the inequality

3x + 16y \leq 19

true?

\newline

Choices:

\newline

(A)yes

\newline

(B)no

Substitute values into inequality: Substitute the values $(1, 1)$ into the inequality $3x + 16y \leq 19$ . The substituted inequality is $3(1) + 16(1) \leq 19$ .
Simplify left side: Simplify the left side of the inequality $3(1) + 16(1)$ to get $3 + 16$ .
Add numbers together: Add the numbers together to get $3 + 16 = 19$ .
Check if statement is true: The inequality now reads $19 \leq 19$ . Determine if this is a true statement.
Verify point satisfies inequality: Since $19$ is equal to $19$ , the inequality $19 \leq 19$ holds true. Therefore, the point $(1, 1)$ does satisfy the inequality $3x + 16y \leq 19$ .

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