Divide the following complex numbers. (-9-6i)/(-3-2i)

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Divide the following complex numbers.  (-9-6i)/(-3-2i)

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Multiply numerator by conjugate: To divide the complex numbers (-9-6i) by (-3-2i), we need to multiply the numerator and the denominator by the conjugate of the denominator to remove the imaginary part from the denominator. The conjugate of (-3-2i) is (-3+2i).Simplify the multiplication: Multiply the numerator (-9-6i) by the conjugate of the denominator (-3+2i). (-9-6i) * (-3+2i) = (-9 * -3) + (-9 * 2i) + (-6i * -3) + (-6i * 2i)Replace i^2 and simplify: Simplify the multiplication. (-9 * -3) + (-9 * 2i) + (-6i * -3) + (-6i * 2i) = 27 - 18i + 18i - 12i^2 Remember that i^2 = -1.Multiply denominator by conjugate: Replace i^2 with -1 and simplify the expression. 27 - 18i + 18i - 12(-1) = 27 + 12 = 39 The imaginary parts cancel out: -18i + 18i = 0Simplify the multiplication: Now, multiply the denominator (-3-2i) by its conjugate (-3+2i). (-3-2i) * (-3+2i) = (-3 * -3) + (-3 * 2i) + (-2i * -3) + (-2i * 2i)Obtain simplified numerator and denominator: Simplify the multiplication. (-3 * -3) + (-3 * 2i) + (-2i * -3) + (-2i * 2i) = 9 - 6i + 6i - 4i^2 Again, replace i^2 with -1.Divide numerator by denominator: Replace i^2 with -1 and simplify the expression. 9 - 6i + 6i - 4(-1) = 9 + 4 = 13 The imaginary parts cancel out: -6i + 6i = 0Now we have the simplified numerator and denominator. The numerator is 39 and the denominator is 13. Divide the numerator by the denominator to get the final result. 39 / 13 = 3

Divide the following complex numbers. $\newline$ $\frac{-9-6 i}{-3-2 i}$

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Divide the following complex numbers.\newline−9−6i−3−2i \frac{-9-6 i}{-3-2 i} −3−2i−9−6i​

Divide the following complex numbers. $\newline$ $\frac{-9-6 i}{-3-2 i}$