Divide the following complex numbers. (-11-3i)/(1-2i)

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Divide the following complex numbers.  (-11-3i)/(1-2i)

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Multiply by conjugate: To divide complex numbers, we multiply the numerator and denominator by the conjugate of the denominator. The conjugate of (1-2i) is (1+2i). (-11-3i)/(1-2i) * (1+2i)/(1+2i)Multiply numerators and denominators: Now, we multiply the numerators together and the denominators together. Numerator: (-11-3i)(1+2i) Denominator: (1-2i)(1+2i)Multiply out the numerator: First, we'll multiply out the numerator. (-11-3i)(1+2i) = -11(1) + -11(2i) + -3i(1) + -3i(2i) = -11 - 22i - 3i - 6i^2 Since i^2 = -1, we replace -6i^2 with 6. = -11 - 22i - 3i + 6 = -5 - 25iMultiply out the denominator: Next, we'll multiply out the denominator. (1-2i)(1+2i) = 1(1) + 1(2i) - 2i(1) - 2i(2i) = 1 + 2i - 2i - 4i^2 Again, since i^2 = -1, we replace -4i^2 with 4. = 1 - 4 = -3Simplify numerator and denominator: Now we have the simplified numerator and denominator. Numerator: -5 - 25i Denominator: -3 We divide the numerator by the denominator. (-5 - 25i) / -3Divide numerator by denominator: Divide each term in the numerator by the denominator. -5 / -3 = 5/3 -25i / -3 = 25i/3 So the division gives us: (5/3) + (25/3)i

Divide the following complex numbers. $\newline$ $\frac{-11-3 i}{1-2 i}$

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Divide the following complex numbers.\newline−11−3i1−2i \frac{-11-3 i}{1-2 i} 1−2i−11−3i​

Divide the following complex numbers. $\newline$ $\frac{-11-3 i}{1-2 i}$