Divide. If there is a remainder, include it as a simplified fraction. (3c^3 - 6c^2 - 9c) ÷ (c - 3) ______

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Divide. If there is a remainder, include it as a simplified fraction.   (3c^3 - 6c^2 - 9c) ÷ (c - 3)    ______

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Use polynomial long division: To divide the polynomial (3c^3 - 6c^2 - 9c) by the binomial (c - 3), we will use polynomial long division.Find first term of quotient: First, we divide the leading term of the polynomial, 3c^3, by the leading term of the binomial, c, to get the first term of the quotient, which is 3c^2. Calculation: (3c^3) ÷ (c) = 3c^2Subtract and continue division: Next, we multiply the entire binomial (c - 3) by the term we just found, 3c^2, and subtract the result from the original polynomial. Calculation: (c - 3) * 3c^2 = 3c^3 - 9c^2 Subtraction: (3c^3 - 6c^2 - 9c) - (3c^3 - 9c^2) = 3c^2 - 9cFind next term of quotient: Now, we divide the leading term of the new polynomial, 3c^2, by the leading term of the binomial, c, to get the next term of the quotient, which is 3c. Calculation: (3c^2) ÷ (c) = 3cSubtract and continue division: We multiply the entire binomial (c - 3) by the term we just found, 3c, and subtract the result from the new polynomial. Calculation: (c - 3) * 3c = 3c^2 - 9c Subtraction: (3c^2 - 9c) - (3c^2 - 9c) = 0Complete division and find quotient: Since we have no remainder, the division is complete. The quotient is the sum of the terms we found: 3c^2 + 3c.

Divide. If there is a remainder, include it as a simplified fraction. $\newline$ $(3c^3 - 6c^2 - 9c) \div (c - 3)$

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Divide. If there is a remainder, include it as a simplified fraction.\newline(3c3−6c2−9c)÷(c−3)(3c^3 - 6c^2 - 9c) \div (c - 3)(3c3−6c2−9c)÷(c−3)

Divide. If there is a remainder, include it as a simplified fraction. $\newline$ $(3c^3 - 6c^2 - 9c) \div (c - 3)$