Q. Divide. If there is a remainder, include it as a simplified fraction.(6g3−20g2+6g)÷(g−3)______
Divide leading terms: We will use polynomial long division to divide (6g3−20g2+6g) by (g−3). First, we divide the leading term of the dividend, 6g3, by the leading term of the divisor, g, to get the first term of the quotient. 6g3÷g=6g2
Multiply and subtract: We multiply the entire divisor (g−3) by the first term of the quotient (6g2) and subtract the result from the dividend.(6g2)⋅(g−3)=6g3−18g2Then we subtract this from the dividend:(6g3−20g2+6g)−(6g3−18g2)=−20g2+18g2+6g=−2g2+6g
Divide new polynomial: Next, we divide the leading term of the new polynomial, −2g2, by the leading term of the divisor, g, to get the next term of the quotient.−2g2÷g=−2g
Multiply and subtract: We multiply the entire divisor (g−3) by the second term of the quotient (−2g) and subtract the result from the new polynomial.(-2g) \cdot (g - 3) = -2g^2 + 6g\(\newlineThen we subtract this from the new polynomial:\$(-2g^2 + 6g) - (-2g^2 + 6g) = 0\)
Complete division process: Since we have no remainder, the division process is complete. The quotient is the sum of the terms we found: \(6g^2 - 2g\).
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