Divide. If there is a remainder, include it as a simplified fraction. (5j^3 - 3j^2 - 2j) ÷ (j - 1) ______

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Divide. If there is a remainder, include it as a simplified fraction.   (5j^3 - 3j^2 - 2j) ÷ (j - 1)    ______

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Divide by First Term: We will use polynomial long division to divide (5j^3 - 3j^2 - 2j) by (j - 1). First, we divide the first term of the dividend, 5j^3, by the first term of the divisor, j, to get the first term of the quotient. 5j^3 ÷ j = 5j^2Subtract and Simplify: Now, we multiply the divisor (j - 1) by the first term of the quotient (5j^2) and subtract the result from the dividend. (5j^3 - 3j^2 - 2j) - (5j^2 * (j - 1)) = (5j^3 - 3j^2 - 2j) - (5j^3 - 5j^2) This simplifies to: -3j^2 - 2j + 5j^2 = 2j^2 - 2jDivide New Dividend: Next, we divide the first term of the new dividend, 2j^2, by the first term of the divisor, j, to get the second term of the quotient. 2j^2 ÷ j = 2jSubtract and Simplify: We multiply the divisor (j - 1) by the second term of the quotient (2j) and subtract the result from the new dividend. (2j^2 - 2j) - (2j * (j - 1)) = (2j^2 - 2j) - (2j^2 - 2j) This simplifies to: -2j + 2j = 0Final Quotient: Since we have no remainder, the division process is complete. The quotient is the sum of the terms we found: 5j^2 + 2j.

Divide. If there is a remainder, include it as a simplified fraction. $\newline$ $(5j^3 - 3j^2 - 2j) \div (j - 1)$

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Divide. If there is a remainder, include it as a simplified fraction.\newline(5j3−3j2−2j)÷(j−1)(5j^3 - 3j^2 - 2j) \div (j - 1)(5j3−3j2−2j)÷(j−1)

Divide. If there is a remainder, include it as a simplified fraction. $\newline$ $(5j^3 - 3j^2 - 2j) \div (j - 1)$