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Divide. If there is a remainder, include it as a simplified fraction. $\newline$ $(-16z^2 - 14z) \div 2z$

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Divide polynomials by monomials

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Q. Divide. If there is a remainder, include it as a simplified fraction.

\newline

(-16z^2 - 14z) \div 2z

Divide Expression: We have the expression to divide: $\newline$ $(-16z^2 - 14z) \div 2z$ $\newline$ First, we will divide each term in the polynomial by the monomial $2z$ . $\newline$ $(-16z^2 - 14z) \div 2z = \frac{-16z^2}{2z} + \frac{-14z}{2z}$
Divide $-16z^2$ by $2z$ : Now let's divide $-16z^2$ by $2z$ : $\frac{-16z^2}{2z} = \frac{-16}{2} \times \frac{z^2}{z} = -8z$ We check for any math errors in this step.
Divide $-14z$ by $2z$ : Next, we divide $-14z$ by $2z$ : $\frac{-14z}{2z} = \frac{-14}{2} \times \frac{z}{z} = -7$ Again, we check for any math errors in this step.
Write Result: Now we can write the result of $\frac{-16z^2}{2z} + \frac{-14z}{2z}$ : $\newline$ $\frac{(-16z^2 - 14z)}{2z} = \frac{-16z^2}{2z} + \frac{-14z}{2z} = -8z - 7$ $\newline$ This is the simplified form of the division, and there is no remainder.

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