Divide. If there is a remainder, include it as a simplified fraction. (2c^2 + 5c - 7) ÷ (c - 1) ______

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Divide. If there is a remainder, include it as a simplified fraction.   (2c^2 + 5c - 7) ÷ (c - 1)    ______

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Divide by First Term: We will use polynomial long division to divide (2c^2 + 5c - 7) by (c - 1). First, we divide the first term of the dividend, 2c^2, by the first term of the divisor, c, to get the first term of the quotient. 2c^2 ÷ c = 2cMultiply and Subtract: Now, we multiply the divisor (c - 1) by the first term of the quotient (2c) and subtract the result from the dividend. (2c)(c - 1) = 2c^2 - 2c Subtract this from the dividend: (2c^2 + 5c - 7) - (2c^2 - 2c) = 5c - 2c - 7 = 3c - 7Divide New Term: Next, we divide the new first term of the remaining polynomial, 3c, by the first term of the divisor, c. 3c ÷ c = 3Multiply and Subtract: We multiply the divisor (c - 1) by the new term of the quotient (3) and subtract the result from the remaining polynomial. (3)(c - 1) = 3c - 3 Subtract this from the remaining polynomial: (3c - 7) - (3c - 3) = -7 + 3 = -4Final Result: Since -4 is a constant and the divisor is a linear term (c - 1), we cannot divide further. Therefore, -4 is the remainder. The quotient is 2c + 3 with a remainder of -4.

Divide. If there is a remainder, include it as a simplified fraction. $\newline$ $(2c^2 + 5c - 7) \div (c - 1)$

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Divide. If there is a remainder, include it as a simplified fraction.\newline(2c2+5c−7)÷(c−1)(2c^2 + 5c - 7) \div (c - 1)(2c2+5c−7)÷(c−1)

Divide. If there is a remainder, include it as a simplified fraction. $\newline$ $(2c^2 + 5c - 7) \div (c - 1)$