Q. Divide. If there is a remainder, include it as a simplified fraction.(k3+4k2−5k)÷(k−1)______
Divide by k: We will use polynomial long division to divide (k3+4k2−5k) by (k−1). First, we divide the first term of the dividend, k3, by the first term of the divisor, k, to get the first term of the quotient. k3÷k=k2
Subtract and Multiply: We multiply the divisor (k−1) by the first term of the quotient k2 and subtract the result from the dividend.(k−1)×k2=k3−k2Subtract this from the dividend:(k3+4k2−5k)−(k3−k2)=4k2−k2−5k=3k2−5k
Divide 3k2 by k: Next, we divide the first term of the new dividend, 3k2, by the first term of the divisor, k, to get the next term of the quotient.3k2÷k=3k
Subtract and Multiply: We multiply the divisor (k−1) by the new term of the quotient (3k) and subtract the result from the new dividend.(k−1)×3k=3k2−3kSubtract this from the new dividend:(3k2−5k)−(3k2−3k)=−5k+3k=−2k
Divide −2k by k: Now, we divide the first term of the new dividend, −2k, by the first term of the divisor, k, to get the next term of the quotient.−2k÷k=−2
Subtract and Multiply: We multiply the divisor (k−1) by the new term of the quotient (−2) and subtract the result from the new dividend.(k−1)×(−2)=−2k+2Subtract this from the new dividend:(−2k)−(−2k+2)=−2k+2k−2=−2
Final Remainder: Since the degree of the remainder (−2) is less than the degree of the divisor (k−1), we cannot continue the division process. The remainder is −2.
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