Divide as indicated. (x^(2)-11 x+36)÷(x-5)

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Divide as indicated.  (x^(2)-11 x+36)÷(x-5)

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Set up division: Set up the long division. We will divide the polynomial (x^2 - 11x + 36) by the binomial (x - 5) using long division.Divide first term: Divide the first term of the dividend by the first term of the divisor. Divide x^2 by x to get x. This will be the first term of the quotient.Multiply divisor: Multiply the divisor by the first term of the quotient. Multiply (x - 5) by x to get x^2 - 5x. Write this below the dividend.Subtract result: Subtract the result from Step 3 from the dividend. Subtract (x^2 - 5x) from (x^2 - 11x + 36) to get -6x + 36.Bring down next term: Bring down the next term of the dividend. There are no more terms to bring down, so we continue with -6x + 36.Divide new first term: Divide the new first term of the remaining dividend by the first term of the divisor. Divide -6x by x to get -6. This will be the next term of the quotient.Multiply new term: Multiply the divisor by the new term of the quotient. Multiply (x - 5) by -6 to get -6x + 30. Write this below the remaining dividend.Subtract result: Subtract the result from Step 7 from the remaining dividend. Subtract (-6x + 30) from (-6x + 36) to get 6.Check remainder: Since the degree of the remainder (0) is less than the degree of the divisor (1), we cannot continue the division. The remainder is 6. The quotient is x - 6 with a remainder of 6.

Divide as indicated. $\newline$ $(x^{2}-11x+36)\div(x-5)$

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Divide as indicated.\newline(x2−11x+36)÷(x−5)(x^{2}-11x+36)\div(x-5)(x2−11x+36)÷(x−5)

Divide as indicated. $\newline$ $(x^{2}-11x+36)\div(x-5)$